X^2+4.8x=0

Solution for X^2+4.8x=0 equation:

X^2+4.8X=0

a = 1; b = 4.8; c = 0;
Δ = b2-4ac
Δ = 4.82-4·1·0
Δ = 23.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.8)-\sqrt{23.04}}{2*1}=\frac{-4.8-\sqrt{23.04}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.8)+\sqrt{23.04}}{2*1}=\frac{-4.8+\sqrt{23.04}}{2}
$